Tu as testé 0 paire
Tu as trouvé 0 paire.
3(d+1)
3d+3
(d+3) × 4
4d+12
d(d+2)
d2+2d
-5(d+1)
-5d-5
-2(d-3)
-2d+6
3d(4-d)
12d-3d2